2[x+1]=3[x+2]

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Solution for 2[x+1]=3[x+2] equation:


Simplifying
2[x + 1] = 3[x + 2]

Reorder the terms:
2[1 + x] = 3[x + 2]
[1 * 2 + x * 2] = 3[x + 2]
[2 + 2x] = 3[x + 2]

Reorder the terms:
2 + 2x = 3[2 + x]
2 + 2x = [2 * 3 + x * 3]
2 + 2x = [6 + 3x]

Solving
2 + 2x = 6 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
2 + 2x + -3x = 6 + 3x + -3x

Combine like terms: 2x + -3x = -1x
2 + -1x = 6 + 3x + -3x

Combine like terms: 3x + -3x = 0
2 + -1x = 6 + 0
2 + -1x = 6

Add '-2' to each side of the equation.
2 + -2 + -1x = 6 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 6 + -2
-1x = 6 + -2

Combine like terms: 6 + -2 = 4
-1x = 4

Divide each side by '-1'.
x = -4

Simplifying
x = -4

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